Find k, if 3 is the zero of $3 x^{2} + (k - 3) x + 9 x = 0$ .

Open in App

Solution

$3$ is the zero of $3 x^{2} + (k - 3) x + 9 x = 0$
Therefore,
$27 + 3 k - 9 + 27 = 0$
$3 k + 45 = 0$
$3 k = - 45$
$k = - 15$

Suggest Corrections

Similar questions

Find $k$ , If $3$ is a solution of $3 x^{2} + (k - 3) x + 0 = 0$

If $p (x) = x^{3} - 3 x^{2} - 9 x - 9$ , find p(0), p(3), p(-3) and p(-1). What do you condlude about the zeros of p(x)? Is 0 a zero p(x)?

3 x + 4 y + 2 = 0

9 x + 12 y + k = 0

k

k

3 x^{2} - k \sqrt{3} x + 4 = 0

3 x^{2} + x y - y^{2} - 3 x + 6 y + k = 0

k =

Join BYJU'S Learning Program