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Question

Find k if one root of the equation x26kx+8=0 is twice the other

A
2
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B
±1
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C
±12
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D
3
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Solution

The correct option is B ±1
since the one root is twice the others,
Let the one root be a and other root will be 2a
Now sum of roots a+2a=6k
and product of roots 2a2=8
a=2,2

Now,
3a=6k
k=a2
Now putting the obtained value of a, we get
k=1,1

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