Question

Find k if the line passing through points P(–12, –3) and Q(4, k) has slope $\frac{1}{2}$.

Answer 1

Slope = $\frac{1}{2}$
Given points are P(–12, –3) and Q(4, k)
Slope of PQ =
$$\begin{gathered} \frac{k+3}{4+12}=\frac{1}{2} \\ \Rightarrow 2k+6=16 \\ \Rightarrow 2k=10 \\ \Rightarrow k=5 \end{gathered}$$