Given ,
(13x2−12y2),(6x2−8y2)
(13x2−12y2),2(3x2−4y2)
Hence HCF is=1
And LCM is
=(13x2−12y2)×2(3x2−4y2)
=2(13x2−12y2)(3x2−4y2)
The LCM of the two numbers is 9 times their HCF. The sum of LCM and HCF is 500. Find their HCF.