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Addition and Subtraction of Algebraic Expression

Find LCM of x...

Question

Find LCM of $x^{2} - 1$ and $x + 1$ .

(x+1)

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$x^{2} - 1$

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(x-1)

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Solution

The correct option is B
$x^{2} - 1$

Given polynomials are $x^{2} - 1$ and $x + 1$ .

$x^{2} - 1 = (x + 1) \times (x - 1)$

Now (x+1) is common in both and the remaining factors are (x-1) and 1.

So, LCM of these polynomials is $(x + 1) \times (x - 1)$

= $x^{2} - 1$

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