Find
${(7 \frac{3}{10})}^{2} - {(2 \frac{1}{10})}^{2}$ .

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Solution

${(7 \frac{3}{10})}^{2} - {(2 \frac{1}{10})}^{2}$

${(\frac{73}{10})}^{2} - {(\frac{21}{10})}^{2}$

$\frac{73^{2} - 21^{2}}{10^{2}} = \frac{5329 - 441}{100}$

$= \frac{4888}{100}$

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Similar questions

{(7 \frac{3}{10})}^{2} - {(2 \frac{1}{10})}^{2}

${(7 \frac{3}{10})}^{2} - {(2 \frac{1}{10})}^{2}$

Q. Factorise:

(7 \frac{3}{10})^{2} - (2 \frac{1}{10})^{2}

Q. Factorise by using formula:

{(7 \frac{3}{10})}^{2} - {(2 \frac{1}{10})}^{2}

48 \frac{22}{25}

If true then enter

1

and if false then enter

0

Factorise:

(i) $4 a^{2} - 25$ (ii) $x^{2} - \frac{9}{16}$ (iii) $x^{4} - y^{4}$ (iv) $[7 \frac{3}{10}]^{2} - [2 \frac{1}{10}]^{2}$ (v) $(0.7)^{2} - (0.3)^{2}$ (vi) $(5 a - 2 b)^{2} - (2 a - b)^{2}$

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Find(7310)2−(2110)2.

(7310)2−(2110)2(7310)2−(2110)2732−212102=5329−441100=4888100

Find
${(7 \frac{3}{10})}^{2} - {(2 \frac{1}{10})}^{2}$ .

${(7 \frac{3}{10})}^{2} - {(2 \frac{1}{10})}^{2}$

${(\frac{73}{10})}^{2} - {(\frac{21}{10})}^{2}$

$\frac{73^{2} - 21^{2}}{10^{2}} = \frac{5329 - 441}{100}$

$= \frac{4888}{100}$