According to law of exponent we have (a^m)^n=a^mn=(a^n)^m. {(4^2)^2}^2=(4^2× 2)^20ex0ex=(4^4)^20ex0ex=4^4× 20ex0ex=4^8Hence, the final answer is 4^8 ...

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Byju's Answer

Standard XII

Physics

Basic Differentiation Rule

Find 4222.

Question

Find ${\{{(4^{2})}^{2}\}}^{2}$ .

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Solution

According to law of exponent we have ${(a^{m})}^{n} = a^{m n} = {(a^{n})}^{m}$ .
${\{{(4^{2})}^{2}\}}^{2} = {(4^{2 \times 2})}^{2} = {(4^{4})}^{2} = 4^{4 \times 2} = 4^{8}$
Hence, the final answer is $4^{8}$

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Find ${\{{(4^{2})}^{2}\}}^{2}$ .

According to law of exponent we have ${(a^{m})}^{n} = a^{m n} = {(a^{n})}^{m}$ .
${\{{(4^{2})}^{2}\}}^{2} = {(4^{2 \times 2})}^{2} = {(4^{4})}^{2} = 4^{4 \times 2} = 4^{8}$
Hence, the final answer is $4^{8}$