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Question

Find (x+y)+(x2+xy+y2)+(x3+x2y+xy2+y3)+... to n terms,

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Solution

It is easy to observe that
x2y2xy=x+y, x3y3xy=x2+xy+y2, etc.
xnynxy=xn1+xn2y+....+xyn2+yn1
L.H.S.=1xy[(x2y2)+(x3y3)+....n terms]
=1xy(S1S2) of a G.P. of n terms
=1xy[x2(1xn)1xy2(1yn)1y]

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