Find (x+y)+(x2+xy+y2)+(x3+x2y+xy2+y3)+... to n terms,
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Solution
It is easy to observe that x2−y2x−y=x+y, x3−y3x−y=x2+xy+y2, etc. xn−ynx−y=xn−1+xn−2y+....+xyn−2+yn−1 L.H.S.=1x−y[(x2−y2)+(x3−y3)+....nterms] =1x−y(S1−S2) of a G.P. of n terms =1x−y[x2(1−xn)1−x−y2(1−yn)1−y]