Findlimx→ 0+sgn(x)+limx→ 0−sgn(x), where sgn(x) represents the signum function
sgn (x) gives the sign of x
That is If x > 0 sgn(x)=1
If x < 0 sgn(x)=−1
and If x = 0 sgn(x)=0
So the graph of sgn (x) will look like
limx→ 0+sign(x) is the value of sign (x) as x approaches zero from right. We can see from graph that it is 1.
limx→ 0−sign(x) is the value of sign (x) as x approaches zero from reft. We can see that the value is -1.
⇒ answer=1+(−1)=0