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Question

Find limit
limx0sin2x+3x2x+sin3x

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Solution

limx0sin2x+3x2x+sin3x
on using L'Hosptal rule we have

limx02cos2x+32+3cos3x

using limit

2×1+32+3×1 = \frac{5}{5} = 1


1212499_1363650_ans_ef85c6b1f0ed45ae95f9b92fc463297b.JPG

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