Question

Find M and Y such that M $\ne$ Y in the addition Y + Y + Y = MY.

• A. M = 2, Y = 5
• B. M = 1, Y = 5
• C. M = 5, Y = 1
• D. M = 3, Y = 5

Answer 1

The correct option is B M = 1, Y = 5

Here, $Y+Y+Y=MY$
$3Y=10M+Y$
$2Y=10M$
$M=\frac{Y}{5}$
So, Y is divisible by 5.
Divisibility of 5 states that a number is divisible by 5 only when the number ends with zero or 5.
Hence Y = 0 or 5.

If Y = 0
Y + Y + Y = 0 + 0 + 0 = 0
then, M = 0
But itt is given that $M\ne Y$, so Y cannot be equal to 0.

If Y = 5
Y + Y + Y = 5 + 5 + 5 = 15
then, MY = 15
$\therefore$ M = 1, Y = 5