Question

Find $m$ if
$(-10{)}^{m-3}\times (-10{)}^5=(-10{)}^{12}$

Answer 1

$(-10{)}^{m-3}\times (-10{)}^5=(-10{)}^{12}$

$(-10{)}^{m-3+5}=(-10{)}^{12}$

$m-3+5=12$ (Equating the powers, since the bases are equal.)

$m=12-5+3$

$m=10$