Question

Find magnitude of angular velocity of the length of hour hand of a wrist watch

Answer 1

Length of hour hand of a wrist watch is 1.5cm

We know,

$\omega =\frac{2\pi }{T}$

where T is the time taken to complete one circle by hour hand, $\omega$ is the angular velocity of hour hand.

$T=12\times 60\times 60sec=43200sec$

$\omega =\frac{2\pi }{43200}$

$\omega =0.000145rad/s$

$\omega =1.454\times {10}^{-4}rad/s$