Consider the given function ,
Let ,y=limx→0(x+1)5x
Apply L-Hospital roll
y=limx→0ddx(x+1)5ddxx
y=limx→05(x+1)4(1+0)1
=limx→0(x+1)4=(0+1)4
y=1
Evaluate limx→0(x+1)5−1x
limx→0x√1+x−√1−x