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Byju's Answer
Standard XII
Mathematics
Existence of Limit
Find: limx →...
Question
Find:
lim
x
→
0
sin
x
−
x
+
1
6
x
3
x
3
.
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Solution
Solution -
lim
x
→
0
s
i
n
x
−
x
+
1
6
x
3
x
3
Apply L-Hospital Rule 3 times
lim
x
→
0
c
o
s
x
−
1
+
1
2
x
2
3
x
2
lim
x
→
0
−
s
i
n
x
+
x
6
x
lim
x
→
0
−
c
o
s
x
+
1
6
=
−
1
+
1
6
=
0
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