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Question

Find matrix X such that 3A2B+3I+X=0 where A=[4213], B=[2132]

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Solution

A=[4213],B=[2132],I=[1001]

Now,
3A2B+3I+X=0

3[4213]2[2132]+3[1001]+X=0

[12639][4264]+[3003]+X=0

[12+4+362+036+094+3]+X=0

[19438]+X=0

X=[19438]

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