CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find matrix X such that 3A2B+3I+X=0 where A=[4213], B=[2132]

Open in App
Solution

A=[4213],B=[2132],I=[1001]

Now,
3A2B+3I+X=0

3[4213]2[2132]+3[1001]+X=0

[12639][4264]+[3003]+X=0

[12+4+362+036+094+3]+X=0

[19438]+X=0

X=[19438]

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Operations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon