Question

Find maximum voltage across $AB$ in the circuit shown in Fig. Assume that diode is ideal

Answer 1

According to the fig diode will act as forward biased and since it is an ideal diode resistance will be zero.

for calculating potential difference along AB we have to calculate , equivalent resistance ,

$\frac{1}{R_{AB}}=\frac{1}{10}+\frac{1}{15}$ ,

we get , $R_{AB}=6k\Omega$

so $R_{e}q=6+5=11k\Omega$

current in the circuit, $I=\frac{30}{11\times {10}^3}$

so $V_{AB}=I\times R_{AB}=\frac{30\times 6\times {10}^3}{11\times {10}^3}=16.36V$