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Question

Find mean deviation about median

Class2−44−66−88−10
Frequency3421

A
1.4
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B
2.4
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C
5.23
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D
7.78
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Solution

The correct option is A 1.4
Class fi Cummulative Frequency(cf) Mid-Valuexi |xiMedian| fi|xiMedian|
24 3 3 3 2 6
46 4 7 5 0 0
68 2 9 7 2 4
810 1 10 9 4 4
N=fi=10
Here, N=10 , so 102=5 and the cummulative frquency is just greater than N2 is 7.
Thus, 46 is median class.
l = lower limit of median class =4
F = Cummulative frequency before median class =3
Difference between the class = h=2
Frequency of median class = f=4
Median =l+N2Ff×h=4+534×2=5
fi×|xiMedian|=14
Mean deviation about the median =1NfI×|xiMedian|=110×14=1.4

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