Question

Find measure of arc $BC$.

• A. ${120}^o$
• B. ${118}^o$
• C. ${110}^o$
• D. ${104}^o$

Answer 1

Answer: (B)

${118}^o$

Diameter of the circle subtends an arc of ${180}^{\circ }$.

Therefore, $arcBE+arcBC={180}^{\circ }$

$\Rightarrow {62}^{\circ }+arcBC={180}^{\circ }$

$\Rightarrow arcBC={180}^{\circ }-{62}^{\circ }={118}^{\circ }$

So, option B is correct