Find median
Class interval 0-2. 2-4 4-6 6-8 8-10 10-12 12-14
Plants. 1. 2. 1. 5. 6. 2. 3
Solution:
Class Interval | Class interval frequency | Cumilative frequency | |
0-2 | 1 | 1 | |
2-4 | 2 | 3 | |
4-6 | 1 | 4 | |
6-8 | 5 | 9 (F) | |
8-10 | 6(f) | 15 | |
10-12 | 2 | 17 | |
12-14 | 3 | 20 | |
N=20 |
We have
N = 20
N/2 = 20/ 2 = 10
The cumulative frequency just greater than N/2 is 10 then 8 – 10 is the median class such, that
L = 8, f = 6, F =9 and h = 10 – 8 = 2
Median = L+((N/2−F)/f)*h(This formula you should know)
=8+(10-9)/6)*h
=8+2/6
=8.33