Find minimum value of \(l\) so that truck can avoid the dead end, without toppling the block kept on it. v
Sufficiemlymfi /
rough >
surface power breaks
A
2hv2bg
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B
3hv22bg
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C
2bv2gh
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D
hv22bg
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Solution
The correct option is Dhv22bg
To avoid toppling, the condition would be mah2≤mgb2⇒a≤bhg
Final velocity of truck is zero. So that 0=v2−2(bhg)l ⇒l=hv22bg