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Question

Find minimum value of μstatic for which the block remains at rest on the stationery wedge.
696522_08db933db7154838aafa069e61b7aa31.png

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Solution

Normal force (N) is

N=mgcosθ+12=mgcos37+12=1×10×45+12=8+12=20N

frictional force,

f=μsN

f=mgsin37

μsN=mgsin37

μs×20=1×10×35

μs×20=6

μs=620=310=0.3

981218_696522_ans_bcc047117582472da298c25e4944b04c.png

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