Find mode for the following data:
X | 2−4 | 4−6 | 6−8 | 8−10 | 10−12 | 12−14 | 14−16 |
F | 1 | 2 | 2 | 3 | 6 | 3 | 2 |
Here frequency of class interval 10−12 is maximum.
So, the modal class is 10−12
Now l = lower limit of modal class =10
f1= frequency of modal class =6
f0= frequency of class preceding the modal class =3
f2= frequency of class succeeding the modal class =3
h= class width =2
So, Mode =l+(f1−f02f1−f0−f2)×h
=10+(6−32×6−3−3)×2
=10+(312−6)×2
=10+(36)×2
=10+1
=11
Hence, mode of the given frequency distribution is 11