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Question

Find mode for the following data:

X
2−4
4−6
6−8
8−10
10−12
12−14
14−16
F
1
2
2
3
6
3
2

A
11
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B
12
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C
13
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D
14
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Solution

The correct option is A 11

Here frequency of class interval 1012 is maximum.

So, the modal class is 1012

Now l = lower limit of modal class =10

f1= frequency of modal class =6

f0= frequency of class preceding the modal class =3

f2= frequency of class succeeding the modal class =3

h= class width =2

So, Mode =l+(f1f02f1f0f2)×h

=10+(632×633)×2

=10+(3126)×2

=10+(36)×2

=10+1

=11

Hence, mode of the given frequency distribution is 11


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