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Byju's Answer
Standard XII
Mathematics
Modulus of a Complex Number
Find modulas ...
Question
Find modulas
(
1
+
√
3
)
+
i
(
1
−
√
3
)
Open in App
Solution
z
=
x
+
i
y
modulus of z:
|
z
|
=
√
x
2
+
y
2
Given,
z
=
(
1
+
√
3
)
+
i
(
1
−
√
3
)
|
z
|
=
√
(
1
+
√
3
)
2
+
(
1
−
√
3
)
2
=
√
1
+
3
+
2
√
3
+
1
+
3
−
2
√
3
=
√
8
=
2
√
2
Modulus of
(
1
+
√
3
)
+
i
(
1
−
√
3
)
=
2
√
2
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0
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Standard XII Mathematics
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