Question

Find modulus and argument of $i$

Answer 1

Let $z=i=0+i$

$\left|z\right|=\sqrt{0+1}=1$

$\tan \theta =\left|\frac{y}{x}\right|=\frac{1}{0}=\infty$

$\Rightarrow \theta =\frac{\pi }{2}$

Therefore Argument of $z$ is $\frac{\pi }{2}$