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Byju's Answer
Standard XII
Chemistry
Characteristics of Chemical Equilibrium
Find moles of...
Question
Find moles of
N
2
O
4
and
N
O
2
at equilibrium are
1
and
2
respectively total pressure at equilibrium is
9
a
t
m
. Find
K
P
for the reaction
N
2
O
4
(
g
)
⇌
2
N
O
2
(
g
)
.
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Solution
N
2
O
4
(
g
)
⇌
2
N
O
2
(
g
)
1
2
total pressure (P) = 9 atm
K
p
=
(
P
N
O
2
)
2
P
N
2
O
4
→
(
1
)
P
N
O
2
=
Y
N
O
2
P
t
o
t
a
l
(from Dalton's law)
where,
Y
N
O
2
=
mole fraction of
N
O
2
∴
P
N
O
2
=
(
2
1
+
2
)
×
9
=
2
3
×
9
=
6
a
t
m
→
(
2
)
and
P
N
2
O
4
=
1
3
×
9
=
3
a
t
m
→
(
3
)
from (1), (2) and (3) we have
K
p
=
6
2
3
=
6
×
6
3
=
12
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Similar questions
Q.
When
36.6
g
N
2
O
4
(
g
)
is introduced into a
1.0
−
l
i
t
r
e
flask at
27
∘
C
. The following equilibrium reaction occurs:
N
2
O
4
(
g
)
⇌
2
N
O
2
(
g
)
;
K
p
=
0.1642
a
t
m
.
(a) Calculate
K
c
of the equilibrium reaction?
(b) What are the number of moles of
N
2
O
4
and
N
O
2
at equilibrium?
(c) What is the total gas pressure in the flask at equilibrium?
(d) What is the percent dissociation of
N
2
O
4
?
Q.
When the reaction,
2
N
O
2
(
g
)
⇌
N
2
O
4
(
g
)
reaches equilibrium at 298 K. The partial pressure of
N
O
2
and
N
2
O
4
are
0.2
K
P
a
and
0.4
K
P
a
, respectively. What is the equilibrium constant
K
p
of the above reaction at
298
K
?
Q.
For the reaction equilibrium
N
2
O
4
⇌
2
N
O
2
(
g
)
, the concentrations of
N
2
O
4
and
N
O
2
at equilibrium are
4.8
×
10
−
2
and
1.2
×
10
−
2
m
o
l
l
i
t
r
e
−
1
respectively. The value of
K
c
for the reaction is:
Q.
The equilibrium constant
K
p
for the reaction
N
2
O
4
(
g
)
⇌
2
N
O
2
(
g
)
is
4.5
What would be the average molar mass (in g/mol) of an equilibrium mixture of
N
2
O
4
and
N
O
2
formed by the dissociation of pure
N
2
O
4
at a total pressure of
2
atm?
Q.
In a container equilibrium
N
2
O
4
(
g
)
⇌
2
N
O
2
(
g
)
is attained at
25
∘
C
. The total equilibrium pressure in container is
380
t
o
r
r
. If equilibrium constant of above equilibrium is
0.667
a
t
m
, then degree of dissociation of
N
2
O
4
at this temperature will be:
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