Question

Find $\mathrm{n}$ factor of ${\mathrm{Na}}_2{\mathrm{CO}}_3$.

Answer 1

n-factor:

1. In the case of acid and base n-factor is calculated as the number of replaceable ${\mathrm{H}}^{+}$ and ${\mathrm{OH}}^{-}$ ion respectively.
2. In the case of salts, n-factor is calculated as the number of electrons exchanged per mole of the salt.
3. ${\mathrm{Na}}_2{\mathrm{CO}}_3\rightleftharpoons 2{\mathrm{Na}}^{+}+{\mathrm{CO}}_3^{2-}$; each $\mathrm{Na}$ atom give $1{\mathrm{e}}^{-}$ so total $2{\mathrm{e}}^{-}$ is being exchanged.
4. So, the n-factor of ${\mathrm{Na}}_2{\mathrm{CO}}_3$ is $2$.