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Question

Find number of digits 1025th terms of the sequence 1,2,2,4,4,4,4,8,8,8,8,8,8,8,8,........ ?

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Solution

The given sequence is 1,2,2,4,4,4,4,8,8,8,8,8,8,8,8,....
The sequence is composed by powers of 2 and repeated 2n times.
We have,
20=1 and 1 appears one time.
21=2 and 2 appears twice.
22=4 and 4 appears four times.
23=8 and 8 appears eight times.
So, the next number will be the next power of 2 and it will appear 2n times.
also, the first 1 is in first position, the first 2 is in second position, the first 4 is in fourth position and so on.
So,
there is one 1, starting from position 1
there are two 2s, starting from position 2
there are four 4s, starting from position 4
there are eight 8s, starting from position 8
....
there are one thousand and twenty four 1024s, starting from position 1024
So, the 1025th number is 1024.

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