Find number of oxygen atoms present in $100 m g$ of $C a C O_{3}$ .
(Atomic Mass of $C a = 40 u, C = 12 u, O = 16$ )

6.02 \times 10^{23}

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6.02 \times 10^{20}

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1.806 \times 10^{21}

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1.204 \times 10^{20}

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Solution

The correct option is C $1.806 \times 10^{21}$
Moles of $C a C O_{3} = \frac{100}{10^{3} \times 100} = 1 m i l l i m o l e s$
Number of oxygen atoms in $C a C O_{3} = 3$
Total number of oxygen atoms in $1 m i l i m o l e s C a C O_{3} = 10^{- 3} \times 3 \times 6.02 \times 10^{23} = 1.806 \times 10^{21}$

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6.02 \times 10^{23})

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