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Question

Find numerically the greatest term in the expansion of (35x)15 when x=15

A
445×312
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B
445×310
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C
455×310
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D
455×312
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Solution

The correct option is D 455×312
(35x)15
=315(15x3)15
Now At x=15 we get
315(113)15
Hence numerically greatest term will be given by
r=(1+n)|x|1+|x|
16.1343
=4
Hence, T5=315.15C4(13)4
=311.1365
=455×312.

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