Find order of reaction for the following
rate = $k [C H C l_{3}] [C l_{2}]^{1 / 2}$

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Solution

The Order of the Reaction is the sum of powers of the reactant concentration.
So the Order is $1 + \frac{1}{2}$ = $\frac{3}{2}$

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Similar questions

C H C l_{3} + C l_{2} \to C C l_{4} + H C l

R a t e = k [C H C l_{3}] [C l_{2}]^{1 / 2}

H_{2} (g) + {C l}_{2} (g) ⟶ 2 H C l (g)

r = k [H_{2}] {[{C l}_{2}]}^{1 / 2}

S O_{2} {C l}_{2} \to S O_{2} + {C l}_{2}

k = 2.2 \times 10^{- 5} s^{- 1}

573

K

S O_{2} {C l}_{2}

573

K

90

m i n

{C H}_{3} C l, {C H}_{2} {C l}_{2}, C H {C l}_{3}, C {C l}_{4}

{C H}_{3} C l > {C H}_{2} {C l}_{2} > C H {C l}_{3} > C {C l}_{4}

1.8 \times 10^{- 2}

500

2 N O C l ⇌ 2 N O + C l_{2}

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