Question

Find ordinate, if abcissa is $8$ and which is at a distance of $6$ from $(2,8)$

• A. $8$
• B. $6$
• C. $0$
• D. None

Answer 1

The correct option is A $8$

Let the required point be $(8,y)$ at a distance of $6$ units from $(2,8)$.

By distance formula, $d=\sqrt{(8-2{)}^2+(y-8{)}^2}$

$d^2=(8-2{)}^2+(y-8{)}^2$

$6^2=6^2+(y-8{)}^2$

$(y-8{)}^2=0$

Hence, $y=8$.