Question

Find out $a\left(6\right)$ in the following finite sequence:
$\frac{2}{7},\frac{4}{7},\frac{6}{7},\frac{8}{7},\frac{10}{7},a\left(6\right)$

• A. $\frac{12}{7}$
• B. $\frac{11}{7}$
• C. $12$
• D. $\frac{8}{7}$

Answer 1

The correct option is A $\frac{12}{7}$

Clearly given sequence is in A.P. with first term and common difference $\frac{2}{7}$

Hence 6th term is given by,

$a_6=a_1+5d=\frac{2}{7}+5\cdot \frac{2}{7}=\frac{12}{7}$