Question

Find out (A + B + C + D) such that AB x CB = DDD where AB and CB are two digit numbers and DDD is a three digit number

• A. 21
• B. 19
• C. 17
• D. 18

Answer 1

The correct option is A 21

$AB\times CB=DDD$
Now DDD has a factor of D or 111
111 has factor 3 or 37
$DDD=37\times 3\times D=AB\times CB$
Thus either AB and CB is 37 and other number is 3\times D.
D=9
$37\times (3\times 9)=999$
$37\times 27=999$
$A=3,B=7,C=2,d=9$
$A+B+C+D=3+7+2+9=21$