Question

# Find out median of the following information: Marks : 10, 70, 50, 20, 95, 55, 42, 60, 48, 80

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Solution

## Arranging the data in ascending order. 10, 20, 42, 48, 50, 55, 60, 70, 80, 95 Here, the number of observations is even. $\mathrm{Median}=\frac{\mathrm{Size}\mathrm{of}{\left(\frac{N}{2}\right)}^{\mathrm{th}}\mathrm{item}+\mathrm{Size}\mathrm{of}{\left(\frac{N}{2}+1\right)}^{\mathrm{th}}\mathrm{item}}{2}\phantom{\rule{0ex}{0ex}}=\frac{\mathrm{Size}\mathrm{of}{\left(\frac{10}{2}\right)}^{\mathrm{th}}\mathrm{item}+\mathrm{Size}\mathrm{of}{\left(\frac{10}{2}+1\right)}^{\mathrm{th}}\mathrm{item}}{2}\phantom{\rule{0ex}{0ex}}=\frac{\mathrm{Size}\mathrm{of}{5}^{\mathrm{th}}\mathrm{item}+\mathrm{Size}\mathrm{of}{6}^{\mathrm{th}}\mathrm{item}}{2}\phantom{\rule{0ex}{0ex}}=\frac{50+55}{2}=52.5$ Thus, median marks is 52.5.

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