Find out median of the following series:

Wage Rate (₹) 25−30 20−25 15−20 10−15 5−10 0−5

Number of Workers 5 10 20 5 8 2

Open in App

Solution

Wages No. of Worker
(f) Cumulative Frequency
(c.f.)

0 − 5
5 − 10
10 − 15
15 − 20
20 − 25
25 − 30 2
8
5
20 (f)
10
5 2
10
15 (c.f.)
35
45
50

N = ∑f = 50

Median class is given by the size of ${(\frac{N}{2})}^{t h}$ item, i.e. ${(\frac{50}{2})}^{t h}$ item, which is 25^th item.
This corresponds to the class interval of (15 − 20), so this is the median class.
$Median = l_{1} + \frac{\frac{N}{2} - c . f .}{f} \times i so, Median = l_{1} + \frac{\frac{50}{2} - c . f .}{f} \times i or, Median = 15 + \frac{25 - 15}{20} \times 5 or, Median = 15 + \frac{50}{20} Thus, Median = 15 + 2.5 = 17.5$

Suggest Corrections

Similar questions

Wages (₹)	0−5	5−10	10−15	15−20	20−25	25−30
Number of Workers	4	6	3	8	12	7

Class Interval	0−5	5−10	10−15	15−20	20−25	25−30
Frequency	20	24	32	28	20	26

Size	0−5	5−10	10−15	15−20	20−25	25−30	30−35	35−40
Frequency	2	5	7	13	21	16	8	3

Wage Rate (₹)	5−15	15−25	25−35	35−45	45−55	55−65
Number of Workers	4	6	10	5	3	2

Find the median for the following frequency distribution table:

Class-intervals	0 - 5	5 -10	10 - 15	15 - 20	20 - 25	25 - 30
Frequency	5	3	9	10	8	5

Join BYJU'S Learning Program