Find out mode from the following data:

Class Interval 5−10 10−15 15−20 20−25 25−30 30−35 35−40

Number of Children 4 5 3 2 6 7 3

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Solution

Class Interval No. of Children
(f)

5 − 10
10 − 15
15 − 20
20 − 25
25 − 30
30 − 35
35 − 40 4
5
3
2
6 = f₀
7 = f₁
3 = f₂

By inspection, we can say that the modal class is (30 – 35) as it has the highest frequency of 7.
$Mode (Z) = l_{1} + \frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}} \times i or, Z = 30 + \frac{7 - 6}{2 (7) - 6 - 3} \times 5 or, Z = 30 + \frac{1}{14 - 9} \times 5 or, Z = 30 + \frac{1}{5} \times 5 or, Z = 30 + 1 = 31 Hence, mode (Z) is 31$

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Similar questions

Class-Interval	0−5	5−10	10−15	15−20	20−25	25−30	30−35	35−40
Frequency	5	7	15	18	16	9	6	3

Size	0−4	4−6	6−10	10−15	15−20	20−30	30−35	35−40
Frequency	2	4	3	5	2	20	6	8

Size	5−10	10−15	15−20	20−25	25−30	30−35	35−40	40−45	45−50
Frequency	6	10	18	30	15	12	10	6	4

Draw 'less than ogive' and 'more than ogive' on a single graph paper and hence find the median of the following data:

Class interval	5−10	10−15	15−20	20−25	25−30	30−35	35−40
Frequency	2	12	2	4	3	4	3

Calculate mode from following data:

$\begin{matrix} Class Interval & 5 - 14 & 15 - 24 & 25 - 34 & 35 - 44 & 44 - 54 & 55 - 64 Frequency & 8 & 10 & 15 & 25 & 40 & 20 \end{matrix}$ .

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Class Interval	No. of Children (f)
5 − 10 10 − 15 15 − 20 20 − 25 25 − 30 30 − 35 35 − 40	4 5 3 2 6 = f₀ 7 = f₁ 3 = f₂