Find out number of reagents which can oxidise Me- O-C - HII2-NaOHIIKMnO4-H-IIITollen-s reagentIVLiAlH4VNaBH4VI SeO2-VII NH2-NH2-NaOH

(I) Iodoform test is given by ethanal. CH_3 CHO + I_2 + NaOH→ CHI_3 + HCOONa So, I_2/ NaOH is an oxidizing agent. (II) KMnO_4 is oxidising agent which oxidize a ...

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Standard XII

Chemistry

Reimer Tiemann Reaction

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Question

Find out number of reagents which can oxidise $M e - O | | C - H$
$(I) I_{2} / N a O H (I I) K M n O_{4} / H^{\oplus} (I I I) Tollen's reagent (I V) L i A l H_{4} (V) N a B H_{4} (V I) S e O_{2} / Δ$
$(V I I) N H_{2} - N H_{2} / N a O H$

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Solution

$(I)$ Iodoform test is given by ethanal.
$C H_{3} - C H O + I_{2} + N a O H \to C H I_{3} + H C O O N a$
So, $I_{2} / N a O H$ is an oxidizing agent.
$(I I) K M n O_{4}$ is oxidising agent which oxidize aldehydes to acid.
$C H_{3} - C H O + K M n O_{4} H^{+} - - \to C H_{3} - C O O H$
$(I I I)$ Tollen's reagent is $[A g (N H_{3})_{2}] O H,$ which is also a oxidizing agent.
$C H_{3} - C H O + 2 [A g (N H_{3})_{2}] O H + H_{2} O \to C H_{3} - C O O H + 2 A g + 4 N H_{3}$
$(I V) L i A l H_{4}$ is reducing agent.
$C H_{3} - C H O + L i A l H_{4} \to C H_{3} C H_{2} O H$
$(V) N a B H_{4}$ is reducing agent.
$C H_{3} - C H O + N a B H_{4} \to C H_{3} C H_{2} O H$
$(V I) S e O_{2}$ is an oxidizing agent which oxidizes ethanal to glyoxal.
$C H_{3} - C H O + S e O_{2} Δ - \to O H C - C H O (Glyoxal)$
$(V I I) C H_{3} - C H O + N H_{2} - N H_{2} N a O H - --- \to C H_{3} - C H_{3} + N_{2}$
Here reduction occurs.
So, $N H_{2} - N H_{2} / N a O H$ is a reducing agent.

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(V I) N H_{2} - N H_{2} / N a O H

Q. Find out number of reagents which can oxidise ethanal.

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K_{2} C r_{2} O_{7}

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K M n O_{4}

C u S O_{4}, H_{2} O_{2}, C l_{2}, O_{3}, F e C l_{3}, H N O_{3}

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N a_{2} S_{2} O_{3}

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i . M e - O | | C - O E t H_{3} O^{+} - -- \to

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{N a}_{2} S_{2} O_{3}

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Find out number of reagents which can oxidise Me−O||C−H (I)I2/NaOH(II)KMnO4/H⊕(III)Tollen's reagent(IV)LiAlH4(V)NaBH4(VI)SeO2/Δ (VII)NH2−NH2/NaOH

Find out number of reagents which can oxidise $M e - O | | C - H$
$(I) I_{2} / N a O H (I I) K M n O_{4} / H^{\oplus} (I I I) Tollen's reagent (I V) L i A l H_{4} (V) N a B H_{4} (V I) S e O_{2} / Δ$
$(V I I) N H_{2} - N H_{2} / N a O H$