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Standard VIII

Chemistry

Properties of Acids

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Question

Find out % of oxalate ion in a given sample of an alkali metal oxalate salt, $0.30$ g of it is dissolved in $100$ mL water and its required $90$ mL of centimolar $K M n O_{4}$ solution in acidic medium:

66%

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55%

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44%

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6.6%

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Solution

The correct option is C 66%
$100 \times \frac{W}{24 + 64} \times 2 = 90 \times \frac{1}{100} \times 5$ ;
$W = 0.198 g$
$%$ of oxalate ion in a given sample
$= \frac{0.198}{0.3} \times 100 = 66$

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Similar questions

0.3 g

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Find out % of oxalate ion in a given sample of an alkali metal oxalate salt, 0.30 g of it is dissolved in 100 mL water and its required 90 mL of centimolar KMnO4 solution in acidic medium:

The correct option is C 66%100×W24+64×2=90×1100×5; W=0.198g % of oxalate ion in a given sample =0.1980.3×100=66

Find out % of oxalate ion in a given sample of an alkali metal oxalate salt, $0.30$ g of it is dissolved in $100$ mL water and its required $90$ mL of centimolar $K M n O_{4}$ solution in acidic medium:

The correct option is C 66%
$100 \times \frac{W}{24 + 64} \times 2 = 90 \times \frac{1}{100} \times 5$ ;
$W = 0.198 g$
$%$ of oxalate ion in a given sample
$= \frac{0.198}{0.3} \times 100 = 66$