Question

Find out oxidation state of $Mn$ in alkaline medium.

• A. $+5$
• B. $+3$
• C. $+7$
• D. $+6$

Answer 1

The correct option is D $+6$

The ratio $100:33.3:20=1:\frac{1}{3}:\frac{1}{5}$

In acidic medium, the equivalent mass $=\frac{FormulamassofKMn{O}_4}{5}$
The oxidation state of Mn changes from +7 to +2.

In neutral medium, the equivalent mass $=\frac{FormulamassofKMn{O}_4}{3}$
The oxidation state of Mn changes from +7 to +4.

In alkaline medium, the equivalent mass $=\frac{FormulamassofKMn{O}_4}{1}$
The oxidation state of Mn changes from +7 to +6.