Find out oxidation states of phosporus in ${P O_{4}}^{3 -}, P_{4} O_{10}$ and ${P_{2} O_{7}}^{4 -}$ .

Open in App

Solution

$P O_{4}^{- 3} \Rightarrow x - 2 \times 4 = - 3 \Rightarrow x = + 5$
$P_{4} O_{10} \Rightarrow 4 x - 2 \times 10 = 0 \Rightarrow 4 x = 20 \Rightarrow x = 5$
$P_{2} O_{7}^{4 -} \Rightarrow 2 x - 14 = - 4 \Rightarrow 2 x = 10 \Rightarrow x = + 5$
Oxidation state of phosphorus in all given compounds is $+ 5$ .

Suggest Corrections

Similar questions

P O_{4}^{3 -}, P_{4} O_{10}

P_{2} O_{7}^{4 -}

P O_{4}^{3 -}, P_{4} O_{10}

P_{2} O_{7}^{4 -}

P O_{4}^{3 -}

P_{2} O_{7}^{4 -}

P H_{4}^{+}, P O_{2}^{3 -}, P O_{4}^{3 -}

P O_{3}^{3 -}

Join BYJU'S Learning Program