Find out standard deviation, given the following data:
8, 10, 12, 14, 16, 18, 20, 22, 24, 26
S. No.SizeDeviation from Assumed AverageSquare of Deviation (X)(dx=X−A)(dx2) A=20 188−20=−1214421010−20=−1010031212−20=−86441414−20=−63651616−20=−41661818−20=−24720 (A)20−20=0082222−20=+2492424−20=+416102626−20=+636N=10 ∑dx=−30∑dx2=420
σ=√∑dx2N−(∑dxN)2=√42010−(−3010)2
=√42−(−3)2=√33=5.74
Standard Deviation = 5.74.