The correct option is B b > c > a > d
Carboxylic group is more acidic than phenol, so its H is the most acidic. Comparing groups (a) and (c), OH group at para to NO2 group is more acidic than OH at meta position with respect to NO2 group because formation of conjugate base (O−) is more stable at para position with respect to NO2 group due to its −M effect (−M effect is applied only at ortho/para position and not to the meta position.) The H present in −C≡CH (group (d)) is least acidic because H is attached in an alkyne system and C is not as electronegative as compared to O atom. So in this case, after removal of H, negative charge on C is not stabilised as much as stabilised at more electronegative O atom and also, there is resonace stabilistion of charge in (a) and (c).
Hence, (b) option is correct.