Question

# Find out the area of the parallelogram whose adjacent sides are ^i+^j+3^k and −^i−2^j+^k

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Solution

## Area of a parallelogram whose adjacent sides are given by →a and →b is given by :Area = ∣∣→a×→b∣∣According to question , →a = ^i+^j+3^k→b = −^i−2^j+^kTherefore, area of the parallelogram is : Area = ∣∣→a×→b∣∣ = ∣∣7^i−4^j−^k∣∣ = √66 square units .

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