Question

Find out the average of 4, 7, 10, 13, ...,28, 31.

• A. 18.5
• B. 16.5
• C. 31
• D. 17.5
• E. 35

Answer 1

The correct option is D 17.5

Here, the difference between any two numbers written in a continuous sequence is 3.
As we know, average of consecutive numbers = \frac{First~number + Last~number}{2}\)
Here, first number = 4 and last number = 31
$\therefore$ Required average $=\frac{4+31}{2}=\frac{35}{2}=17.5$