Question

Find out the correct reading on ammeter 2?

• A. 0
• B. 1A
• C. 2A
• D. 3A
• E. 6A

Answer 1

The correct option is B 1A

Given the resistors $3\Omega$ and $6\Omega$ are connected in parallel to 6 V battery.

Thus the potential drop across $R=6\Omega$ is $V=6V$.

From Ohm's law: $I=V/R$

The reading of $A_2$ will be $I=\frac{6V}{6\Omega }=1A$.

$\Rightarrow$option B is correct.