Find out the distance travelled by the block on incline before it stops. Initial velocity of the block is 10m/s and co-efficient of friction between the block and incline is μ=0.5. (Takeg=10m/s2)
A
5 m
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B
4 m
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C
10 m
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D
6 m
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Solution
The correct option is A5 m FBD,
We get normal force on block by equating the normal component of weight perpendicular to inclined plane N=mgcos37∘
Applying Newton's law along the inclined plane we get, ∴−mgsin37∘−μN=ma a=−10m/s2
Now by the equation of motion, v2=u2+2as 0=102+2(−10)S ∴S=5m