Find out the efficiency of the heat engine if it produces $100 J$ of heat, does $30 J$ of work, and emits $70 J$ into a cold reservoir.

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

70

No worries! We‘ve got your back. Try BYJU‘S free classes today!

42

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E $30$ %
Efficiency of a heat engine is given by ,
$η = \frac{W}{Q_{1}}$
where $W =$ net work done /cycle and $Q_{1} =$ total heat absorbed / cycle
given - $W = 30 J$ , $Q_{1} = 100 J$
therefore $η = \frac{30}{100} \times 100 = 30$ %

Suggest Corrections

Similar questions

Q. A heat engine produces 100 J of heat, does 30 J of work, and emits 70 J into a cold reservoir. What is the efficiency of the heat engine?

Again, the engine does 41,000 J of useful work. If it sinks 9,000 J of energy in the form of heat to its cold reservoir, what is the efficiency of this engine?

Q. A heat engine takes in

900 J

of heat from a high-temperature reservoir and produces

300 J

of work in each cycle. What is its efficiency?

Q. An engine does 41,000 J of useful work. If it sinks 9,000 J of energy in the form of heat to its cold reservoir, find the heat energy supplied to the engine's hot reservoir?

Join BYJU'S Learning Program

Find out the efficiency of the heat engine if it produces 100J of heat, does 30J of work, and emits 70J into a cold reservoir.

The correct option is E 30%Efficiency of a heat engine is given by , η=WQ1 where W= net work done /cycle and Q1=total heat absorbed / cycle given - W=30J , Q1=100J therefore η=30100×100=30%

Find out the efficiency of the heat engine if it produces $100 J$ of heat, does $30 J$ of work, and emits $70 J$ into a cold reservoir.

The correct option is E $30$ %
Efficiency of a heat engine is given by ,
$η = \frac{W}{Q_{1}}$
where $W =$ net work done /cycle and $Q_{1} =$ total heat absorbed / cycle
given - $W = 30 J$ , $Q_{1} = 100 J$
therefore $η = \frac{30}{100} \times 100 = 30$ %