Question

Find out the first term of the arithmetic progression whose $6^{th}$ term is $29$ and also whose common difference is $3$.

Answer 1

Now, it is given that the $t_6=29$. Also $d=3$.

To find the value of a, we can use the formula

$t_n=a+(n-1)d$

Thus, $t_6=a+(6-1)3$

$29=a+15$

Or, $a=29-15=14$

Thus, the first term of the required A.P. is $14$.