(a) Effective resistance of the resistors connected in parallel is given by,
1R=1R1+1R2
1R=18+18
R=R1×R2R1+R2
R=(8×88+8)=4Ω
(b) Total resistance = 4+4 = 8Ω
I=VR=88=1 A
(c) Potential drop = IR = 1 × 4 = 4V
(d) Power dissipated =I2R=(1)24=4W
(e) The same current flows through each element in a series circuit. Therefore, there is no difference.